1111132204133 has 4 divisors (see below), whose sum is σ = 1269865376160. Its totient is φ = 952399032108.

The previous prime is 1111132204097. The next prime is 1111132204151. The reversal of 1111132204133 is 3314022311111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1111132204133 - 2⁶ = 1111132204069 is a prime.

It is a super-2 number, since 2×1111132204133² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1111132204099 and 1111132204108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1111132224133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79366586003 + ... + 79366586016.

It is an arithmetic number, because the mean of its divisors is an integer number (317466344040).

Almost surely, 2^{1111132204133} is an apocalyptic number.

It is an amenable number.

1111132204133 is a deficient number, since it is larger than the sum of its proper divisors (158733172027).

1111132204133 is an equidigital number, since it uses as much as digits as its factorization.

1111132204133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 158733172026.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1111132204133 its reverse (3314022311111), we get a palindrome (4425154515244).

The spelling of 1111132204133 in words is "one trillion, one hundred eleven billion, one hundred thirty-two million, two hundred four thousand, one hundred thirty-three".