Base | Representation |
---|---|
bin | 110011101111011011… |
… | …1101001101101001111 |
3 | 101121210200022010211201 |
4 | 1213132313221231033 |
5 | 3310030002004403 |
6 | 123013355530331 |
7 | 11012330402152 |
oct | 1473667515517 |
9 | 347720263751 |
10 | 111113313103 |
11 | 43139628791 |
12 | 1964b7599a7 |
13 | a62a05c460 |
14 | 5540dc9c99 |
15 | 2d54c0d21d |
hex | 19dede9b4f |
111113313103 has 12 divisors (see below), whose sum is σ = 121654349544. Its totient is φ = 100884679200.
The previous prime is 111113313061. The next prime is 111113313107. The reversal of 111113313103 is 301313311111.
It is not a de Polignac number, because 111113313103 - 217 = 111113182031 is a prime.
It is a super-2 number, since 2×1111133131032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111113313107) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1100133 + ... + 1196878.
It is an arithmetic number, because the mean of its divisors is an integer number (10137862462).
Almost surely, 2111113313103 is an apocalyptic number.
111113313103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
111113313103 is a deficient number, since it is larger than the sum of its proper divisors (10541036441).
111113313103 is an equidigital number, since it uses as much as digits as its factorization.
111113313103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2297146 (or 2297085 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 111113313103 its reverse (301313311111), we get a palindrome (412426624214).
The spelling of 111113313103 in words is "one hundred eleven billion, one hundred thirteen million, three hundred thirteen thousand, one hundred three".
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