1111133420231 has 4 divisors (see below), whose sum is σ = 1129348722264. Its totient is φ = 1092918118200.

The previous prime is 1111133420179. The next prime is 1111133420239. The reversal of 1111133420231 is 1320243311111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1111133420231 is a prime.

It is a super-2 number, since 2×1111133420231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1111133420197 and 1111133420206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1111133420239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9107650925 + ... + 9107651046.

It is an arithmetic number, because the mean of its divisors is an integer number (282337180566).

Almost surely, 2^{1111133420231} is an apocalyptic number.

1111133420231 is a deficient number, since it is larger than the sum of its proper divisors (18215302033).

1111133420231 is an equidigital number, since it uses as much as digits as its factorization.

1111133420231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18215302032.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1111133420231 its reverse (1320243311111), we get a palindrome (2431376731342).

The spelling of 1111133420231 in words is "one trillion, one hundred eleven billion, one hundred thirty-three million, four hundred twenty thousand, two hundred thirty-one".