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111113345566709 is a prime number
BaseRepresentation
bin11001010000111010010111…
…011111100000011111110101
3112120102022222002122120201022
4121100322113133200133311
5104030440112431113314
61032152433303110525
732255450166633053
oct3120722737403765
9476368862576638
10111113345566709
11324499a5942a62
1210566616742445
1349ccc35c11765
141d61cb3a091d3
15cca4a6b2578e
hex650e977e07f5

111113345566709 has 2 divisors, whose sum is σ = 111113345566710. Its totient is φ = 111113345566708.

The previous prime is 111113345566687. The next prime is 111113345566801. The reversal of 111113345566709 is 907665543311111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 57947446231684 + 53165899335025 = 7612322^2 + 7291495^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111113345566709 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111113345560709) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556672783354 + 55556672783355.

It is an arithmetic number, because the mean of its divisors is an integer number (55556672783355).

Almost surely, 2111113345566709 is an apocalyptic number.

It is an amenable number.

111113345566709 is a deficient number, since it is larger than the sum of its proper divisors (1).

111113345566709 is an equidigital number, since it uses as much as digits as its factorization.

111113345566709 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2041200, while the sum is 53.

The spelling of 111113345566709 in words is "one hundred eleven trillion, one hundred thirteen billion, three hundred forty-five million, five hundred sixty-six thousand, seven hundred nine".