11111345583 has 12 divisors (see below), whose sum is σ = 16042416840. Its totient is φ = 6837750816.

The previous prime is 11111345579. The next prime is 11111345587. The reversal of 11111345583 is 38554311111.

It is an interprime number because it is at equal distance from previous prime (11111345579) and next prime (11111345587).

It is not a de Polignac number, because 11111345583 - 2² = 11111345579 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11111345587) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10957428 + ... + 10958441.

It is an arithmetic number, because the mean of its divisors is an integer number (1336868070).

Almost surely, 2^11111345583 is an apocalyptic number.

11111345583 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11111345583 is a deficient number, since it is larger than the sum of its proper divisors (4931071257).

11111345583 is a wasteful number, since it uses less digits than its factorization.

11111345583 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21915898 (or 21915885 counting only the distinct ones).

The product of its digits is 7200, while the sum is 33.

Adding to 11111345583 its reverse (38554311111), we get a palindrome (49665656694).

The spelling of 11111345583 in words is "eleven billion, one hundred eleven million, three hundred forty-five thousand, five hundred eighty-three".