11111440113041 has 2 divisors, whose sum is σ = 11111440113042. Its totient is φ = 11111440113040.

The previous prime is 11111440112977. The next prime is 11111440113043. The reversal of 11111440113041 is 14031104411111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9223369000000 + 1888071113041 = 3037000^2 + 1374071^2 .

It is an emirp because it is prime and its reverse (14031104411111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11111440113041 - 2⁶ = 11111440112977 is a prime.

Together with 11111440113043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11111440112998 and 11111440113016.

It is not a weakly prime, because it can be changed into another prime (11111440113043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555720056520 + 5555720056521.

It is an arithmetic number, because the mean of its divisors is an integer number (5555720056521).

Almost surely, 2^{11111440113041} is an apocalyptic number.

It is an amenable number.

11111440113041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111440113041 is an equidigital number, since it uses as much as digits as its factorization.

11111440113041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 23.

Adding to 11111440113041 its reverse (14031104411111), we get a palindrome (25142544524152).

The spelling of 11111440113041 in words is "eleven trillion, one hundred eleven billion, four hundred forty million, one hundred thirteen thousand, forty-one".