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11111444222113 is a prime number
BaseRepresentation
bin1010000110110001010110…
…1011111001000010100001
31110100020120122121201222101
42201230111223321002201
52424022214210101423
635344305500010401
72224526642351014
oct241542553710241
943306518551871
1011111444222113
1135a4378652514
1212b5580230a01
13627a5cbb3c51
142a5b2249d37b
1514407a47e7ad
hexa1b15af90a1

11111444222113 has 2 divisors, whose sum is σ = 11111444222114. Its totient is φ = 11111444222112.

The previous prime is 11111444222101. The next prime is 11111444222147. The reversal of 11111444222113 is 31122244411111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10385460131904 + 725984090209 = 3222648^2 + 852047^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11111444222113 is a prime.

It is a super-2 number, since 2×111114442221132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11111444232113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555722111056 + 5555722111057.

It is an arithmetic number, because the mean of its divisors is an integer number (5555722111057).

Almost surely, 211111444222113 is an apocalyptic number.

It is an amenable number.

11111444222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111444222113 is an equidigital number, since it uses as much as digits as its factorization.

11111444222113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1536, while the sum is 28.

Adding to 11111444222113 its reverse (31122244411111), we get a palindrome (42233688633224).

The spelling of 11111444222113 in words is "eleven trillion, one hundred eleven billion, four hundred forty-four million, two hundred twenty-two thousand, one hundred thirteen".