Base | Representation |
---|---|
bin | 1010000110110001010110… |
… | …1011111001000011000011 |
3 | 1110100020120122121202000122 |
4 | 2201230111223321003003 |
5 | 2424022214210102042 |
6 | 35344305500010455 |
7 | 2224526642351063 |
oct | 241542553710303 |
9 | 43306518552018 |
10 | 11111444222147 |
11 | 35a4378652545 |
12 | 12b5580230a2b |
13 | 627a5cbb3c79 |
14 | 2a5b2249d3a3 |
15 | 14407a47e7d2 |
hex | a1b15af90c3 |
11111444222147 has 2 divisors, whose sum is σ = 11111444222148. Its totient is φ = 11111444222146.
The previous prime is 11111444222113. The next prime is 11111444222149. The reversal of 11111444222147 is 74122244411111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11111444222147 - 26 = 11111444222083 is a prime.
Together with 11111444222149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11111444222149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555722111073 + 5555722111074.
It is an arithmetic number, because the mean of its divisors is an integer number (5555722111074).
Almost surely, 211111444222147 is an apocalyptic number.
11111444222147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111444222147 is an equidigital number, since it uses as much as digits as its factorization.
11111444222147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 14336, while the sum is 35.
Adding to 11111444222147 its reverse (74122244411111), we get a palindrome (85233688633258).
The spelling of 11111444222147 in words is "eleven trillion, one hundred eleven billion, four hundred forty-four million, two hundred twenty-two thousand, one hundred forty-seven".
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