Base | Representation |
---|---|
bin | 110011101111101000… |
… | …1001111011001101111 |
3 | 101121211010220221111011 |
4 | 1213133101033121233 |
5 | 3310033211133403 |
6 | 123014155410051 |
7 | 11012441411050 |
oct | 1473721173157 |
9 | 347733827434 |
10 | 111120021103 |
11 | 4314239a593 |
12 | 19651a53927 |
13 | a62b56a7a0 |
14 | 5541c54727 |
15 | 2d555d5a6d |
hex | 19df44f66f |
111120021103 has 32 divisors (see below), whose sum is σ = 137421025280. Its totient is φ = 87497262720.
The previous prime is 111120021071. The next prime is 111120021109. The reversal of 111120021103 is 301120021111.
It is a happy number.
It is not a de Polignac number, because 111120021103 - 25 = 111120021071 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (13).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111120021109) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16815226 + ... + 16821832.
It is an arithmetic number, because the mean of its divisors is an integer number (4294407040).
Almost surely, 2111120021103 is an apocalyptic number.
111120021103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
111120021103 is a deficient number, since it is larger than the sum of its proper divisors (26301004177).
111120021103 is a wasteful number, since it uses less digits than its factorization.
111120021103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7487.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 111120021103 its reverse (301120021111), we get a palindrome (412240042214).
The spelling of 111120021103 in words is "one hundred eleven billion, one hundred twenty million, twenty-one thousand, one hundred three".
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