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11112031212013 = 11819409001873
BaseRepresentation
bin1010000110110011100010…
…1011000101000111101101
31110100022002120010220202001
42201230320223011013231
52424024414442241023
635344444025132301
72224550330602564
oct241547053050755
943308076126661
1011112031212013
1135a4649a24736
1212b570492a091
13627b246a5b54
142a5b7a41abdb
151440b1c7c6ad
hexa1b38ac51ed

11112031212013 has 4 divisors (see below), whose sum is σ = 11121440215068. Its totient is φ = 11102622208960.

The previous prime is 11112031211987. The next prime is 11112031212031. The reversal of 11112031212013 is 31021213021111.

11112031212013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6441535368324 + 4670495843689 = 2538018^2 + 2161133^2 .

It is a cyclic number.

It is not a de Polignac number, because 11112031212013 - 233 = 11103441277421 is a prime.

It is a super-2 number, since 2×111120312120132 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11112031212413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4704499756 + ... + 4704502117.

It is an arithmetic number, because the mean of its divisors is an integer number (2780360053767).

Almost surely, 211112031212013 is an apocalyptic number.

It is an amenable number.

11112031212013 is a deficient number, since it is larger than the sum of its proper divisors (9409003055).

11112031212013 is an equidigital number, since it uses as much as digits as its factorization.

11112031212013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9409003054.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 11112031212013 its reverse (31021213021111), we get a palindrome (42133244233124).

The spelling of 11112031212013 in words is "eleven trillion, one hundred twelve billion, thirty-one million, two hundred twelve thousand, thirteen".

Divisors: 1 1181 9409001873 11112031212013