Base | Representation |
---|---|
bin | 1010000110110011110011… |
… | …0001011111000101100001 |
3 | 1110100022021100120201020212 |
4 | 2201230330301133011201 |
5 | 2424030040100000342 |
6 | 35344454523343505 |
7 | 2224552124361125 |
oct | 241547461370541 |
9 | 43308240521225 |
10 | 11112100000097 |
11 | 35a4684838198 |
12 | 12b5723981b95 |
13 | 627b35a0bb65 |
14 | 2a5b85605585 |
15 | 1440b7d19182 |
hex | a1b3cc5f161 |
11112100000097 has 2 divisors, whose sum is σ = 11112100000098. Its totient is φ = 11112100000096.
The previous prime is 11112100000093. The next prime is 11112100000139. The reversal of 11112100000097 is 79000000121111.
It is a happy number.
11112100000097 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10322141670481 + 789958329616 = 3212809^2 + 888796^2 .
It is a cyclic number.
It is not a de Polignac number, because 11112100000097 - 22 = 11112100000093 is a prime.
It is not a weakly prime, because it can be changed into another prime (11112100000093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556050000048 + 5556050000049.
It is an arithmetic number, because the mean of its divisors is an integer number (5556050000049).
Almost surely, 211112100000097 is an apocalyptic number.
It is an amenable number.
11112100000097 is a deficient number, since it is larger than the sum of its proper divisors (1).
11112100000097 is an equidigital number, since it uses as much as digits as its factorization.
11112100000097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 23.
The spelling of 11112100000097 in words is "eleven trillion, one hundred twelve billion, one hundred million, ninety-seven", and thus it is an aban number.
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