Base | Representation |
---|---|
bin | 1010000110110100001101… |
… | …1101011111101100001010 |
3 | 1110100022120011201001212022 |
4 | 2201231003131133230022 |
5 | 2424030302310401302 |
6 | 35344514012244442 |
7 | 2224554656145131 |
oct | 241550335375412 |
9 | 43308504631768 |
10 | 11112212200202 |
11 | 35a4732101853 |
12 | 12b5755470722 |
13 | 627b53034759 |
14 | 2a5b96490918 |
15 | 1440c2acd8a2 |
hex | a1b4375fb0a |
11112212200202 has 4 divisors (see below), whose sum is σ = 16668318300306. Its totient is φ = 5556106100100.
The previous prime is 11112212200169. The next prime is 11112212200253. The reversal of 11112212200202 is 20200221221111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9548909597161 + 1563302603041 = 3090131^2 + 1250321^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2778053050049 + ... + 2778053050052.
Almost surely, 211112212200202 is an apocalyptic number.
11112212200202 is a deficient number, since it is larger than the sum of its proper divisors (5556106100104).
11112212200202 is an equidigital number, since it uses as much as digits as its factorization.
11112212200202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5556106100103.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 11112212200202 its reverse (20200221221111), we get a palindrome (31312433421313).
The spelling of 11112212200202 in words is "eleven trillion, one hundred twelve billion, two hundred twelve million, two hundred thousand, two hundred two".
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