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111122220031 is a prime number
BaseRepresentation
bin110011101111101100…
…1101000001111111111
3101121211022001122211221
41213133121220033333
53310034242020111
6123014314454211
711012466166654
oct1473731501777
9347738048757
10111122220031
1143143661689
1219652734367
13a62bb5a624
145542267c2b
152d558bc371
hex19df6683ff

111122220031 has 2 divisors, whose sum is σ = 111122220032. Its totient is φ = 111122220030.

The previous prime is 111122220029. The next prime is 111122220059. The reversal of 111122220031 is 130022221111.

It is a weak prime.

It is an emirp because it is prime and its reverse (130022221111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111122220031 - 21 = 111122220029 is a prime.

It is a super-2 number, since 2×1111222200312 (a number of 23 digits) contains 22 as substring.

Together with 111122220029, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 111122219987 and 111122220014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111122230031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55561110015 + 55561110016.

It is an arithmetic number, because the mean of its divisors is an integer number (55561110016).

Almost surely, 2111122220031 is an apocalyptic number.

111122220031 is a deficient number, since it is larger than the sum of its proper divisors (1).

111122220031 is an equidigital number, since it uses as much as digits as its factorization.

111122220031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 111122220031 its reverse (130022221111), we get a palindrome (241144441142).

The spelling of 111122220031 in words is "one hundred eleven billion, one hundred twenty-two million, two hundred twenty thousand, thirty-one".