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11112302143 is a prime number
BaseRepresentation
bin10100101100101100…
…00100011000111111
31001200102202102211001
422112112010120333
5140224222132033
65034355111131
7542242003225
oct122626043077
931612672731
1011112302143
114792672088
1221a15a24a7
131081287817
14775b84b15
15450873e7d
hex29658463f

11112302143 has 2 divisors, whose sum is σ = 11112302144. Its totient is φ = 11112302142.

The previous prime is 11112302101. The next prime is 11112302153. The reversal of 11112302143 is 34120321111.

11112302143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (34120321111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11112302143 - 29 = 11112301631 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11112302143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11112302153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556151071 + 5556151072.

It is an arithmetic number, because the mean of its divisors is an integer number (5556151072).

Almost surely, 211112302143 is an apocalyptic number.

11112302143 is a deficient number, since it is larger than the sum of its proper divisors (1).

11112302143 is an equidigital number, since it uses as much as digits as its factorization.

11112302143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11112302143 its reverse (34120321111), we get a palindrome (45232623254).

The spelling of 11112302143 in words is "eleven billion, one hundred twelve million, three hundred two thousand, one hundred forty-three".