1111231300013 has 2 divisors, whose sum is σ = 1111231300014. Its totient is φ = 1111231300012.

The previous prime is 1111231299991. The next prime is 1111231300031. The reversal of 1111231300013 is 3100031321111.

Together with next prime (1111231300031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1094948774404 + 16282525609 = 1046398^2 + 127603^2 .

It is an emirp because it is prime and its reverse (3100031321111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1111231300013 - 2³² = 1106936332717 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1111231299964 and 1111231300000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111231300063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555615650006 + 555615650007.

It is an arithmetic number, because the mean of its divisors is an integer number (555615650007).

Almost surely, 2^{1111231300013} is an apocalyptic number.

It is an amenable number.

1111231300013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111231300013 is an equidigital number, since it uses as much as digits as its factorization.

1111231300013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1111231300013 its reverse (3100031321111), we get a palindrome (4211262621124).

The spelling of 1111231300013 in words is "one trillion, one hundred eleven billion, two hundred thirty-one million, three hundred thousand, thirteen".