111130013032133 has 4 divisors (see below), whose sum is σ = 111132884721600. Its totient is φ = 111127141342668.

The previous prime is 111130013032039. The next prime is 111130013032153. The reversal of 111130013032133 is 331230310031111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111130013032133 - 2¹⁸ = 111130012769989 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111130013032099 and 111130013032108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111130013032153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1435786685 + ... + 1435864082.

It is an arithmetic number, because the mean of its divisors is an integer number (27783221180400).

Almost surely, 2^{111130013032133} is an apocalyptic number.

It is an amenable number.

111130013032133 is a deficient number, since it is larger than the sum of its proper divisors (2871689467).

111130013032133 is an equidigital number, since it uses as much as digits as its factorization.

111130013032133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2871689466.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 111130013032133 its reverse (331230310031111), we get a palindrome (442360323063244).

The spelling of 111130013032133 in words is "one hundred eleven trillion, one hundred thirty billion, thirteen million, thirty-two thousand, one hundred thirty-three".