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11113003140 = 2235185216719
BaseRepresentation
bin10100101100110001…
…01111100010000100
31001200111002001101220
422112120233202010
5140224412100030
65034422120340
7542250653031
oct122630574204
931614061356
1011113003140
114793000818
1221a18800b0
131081471905
14775cc8388
15450961a10
hex29662f884

11113003140 has 24 divisors (see below), whose sum is σ = 31116408960. Its totient is φ = 2963467488.

The previous prime is 11113003133. The next prime is 11113003151. The reversal of 11113003140 is 4130031111.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 92608300 + ... + 92608419.

It is an arithmetic number, because the mean of its divisors is an integer number (1296517040).

Almost surely, 211113003140 is an apocalyptic number.

11113003140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11113003140 is an abundant number, since it is smaller than the sum of its proper divisors (20003405820).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11113003140 is a wasteful number, since it uses less digits than its factorization.

11113003140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 185216731 (or 185216729 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 11113003140 its reverse (4130031111), we get a palindrome (15243034251).

The spelling of 11113003140 in words is "eleven billion, one hundred thirteen million, three thousand, one hundred forty".

Divisors: 1 2 3 4 5 6 10 12 15 20 30 60 185216719 370433438 555650157 740866876 926083595 1111300314 1852167190 2222600628 2778250785 3704334380 5556501570 11113003140