11113102121 has 4 divisors (see below), whose sum is σ = 12123384144. Its totient is φ = 10102820100.

The previous prime is 11113102103. The next prime is 11113102129. The reversal of 11113102121 is 12120131111.

11113102121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12120131111 = 11 ⋅1101830101.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11113102121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11113102096 and 11113102105.

It is not an unprimeable number, because it can be changed into a prime (11113102129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505140995 + ... + 505141016.

It is an arithmetic number, because the mean of its divisors is an integer number (3030846036).

Almost surely, 2^11113102121 is an apocalyptic number.

11113102121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

11113102121 is a deficient number, since it is larger than the sum of its proper divisors (1010282023).

11113102121 is a wasteful number, since it uses less digits than its factorization.

11113102121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1010282022.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 11113102121 its reverse (12120131111), we get a palindrome (23233233232).

The spelling of 11113102121 in words is "eleven billion, one hundred thirteen million, one hundred two thousand, one hundred twenty-one".