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1111311202103 is a prime number
BaseRepresentation
bin10000001010111111010…
…011110011011100110111
310221020111012002100222222
4100022333103303130313
5121201431131431403
62210310155512555
7143201220234104
oct20127723633467
93836435070888
101111311202103
11399339224603
1215b467a5875b
1380a4732347b
143bb05825aab
151dd93a13338
hex102bf4f3737

1111311202103 has 2 divisors, whose sum is σ = 1111311202104. Its totient is φ = 1111311202102.

The previous prime is 1111311202033. The next prime is 1111311202139. The reversal of 1111311202103 is 3012021131111.

It is a strong prime.

It is an emirp because it is prime and its reverse (3012021131111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1111311202103 - 216 = 1111311136567 is a prime.

It is a super-2 number, since 2×11113112021032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111311204103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555655601051 + 555655601052.

It is an arithmetic number, because the mean of its divisors is an integer number (555655601052).

Almost surely, 21111311202103 is an apocalyptic number.

1111311202103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111311202103 is an equidigital number, since it uses as much as digits as its factorization.

1111311202103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1111311202103 its reverse (3012021131111), we get a palindrome (4123332333214).

The spelling of 1111311202103 in words is "one trillion, one hundred eleven billion, three hundred eleven million, two hundred two thousand, one hundred three".