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11113112022103 = 713373327405121
BaseRepresentation
bin1010000110110111100100…
…0110000010110001010111
31110100101212212212202110101
42201231321012002301113
52424034123134201403
635345143154434531
72224616163412450
oct241557106026127
943311785782411
1011113112022103
1135a5054022313
1212b5966892a47
13627c67598050
142a5c3dba2127
15144126ac271d
hexa1b79182c57

11113112022103 has 16 divisors (see below), whose sum is σ = 13714345750336. Its totient is φ = 8769218734080.

The previous prime is 11113112022091. The next prime is 11113112022109. The reversal of 11113112022103 is 30122021131111.

It is not a de Polignac number, because 11113112022103 - 217 = 11113111891031 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11113112022109) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 163668618 + ... + 163736503.

It is an arithmetic number, because the mean of its divisors is an integer number (857146609396).

Almost surely, 211113112022103 is an apocalyptic number.

11113112022103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11113112022103 is a deficient number, since it is larger than the sum of its proper divisors (2601233728233).

11113112022103 is a wasteful number, since it uses less digits than its factorization.

11113112022103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 327405514.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 11113112022103 its reverse (30122021131111), we get a palindrome (41235133153214).

The spelling of 11113112022103 in words is "eleven trillion, one hundred thirteen billion, one hundred twelve million, twenty-two thousand, one hundred three".

Divisors: 1 7 13 91 373 2611 4849 33943 327405121 2291835847 4256266573 29793866011 122122110133 854854770931 1587587431729 11113112022103