Base | Representation |
---|---|
bin | 101010011001… |
… | …001010100000 |
3 | 202220121100001 |
4 | 222121022200 |
5 | 10321104440 |
6 | 1034105344 |
7 | 163313524 |
oct | 52311240 |
9 | 22817301 |
10 | 11113120 |
11 | 63004a7 |
12 | 387b254 |
13 | 23c1415 |
14 | 1693d84 |
15 | e97b9a |
hex | a992a0 |
11113120 has 24 divisors (see below), whose sum is σ = 26255124. Its totient is φ = 4445184.
The previous prime is 11113111. The next prime is 11113129. The reversal of 11113120 is 2131111.
It is an interprime number because it is at equal distance from previous prime (11113111) and next prime (11113129).
It can be written as a sum of positive squares in 2 ways, for example, as 10214416 + 898704 = 3196^2 + 948^2 .
It is a super-2 number, since 2×111131202 = 247002872268800, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (10).
It is a junction number, because it is equal to n+sod(n) for n = 11113097 and 11113106.
It is not an unprimeable number, because it can be changed into a prime (11113129) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34569 + ... + 34888.
Almost surely, 211113120 is an apocalyptic number.
11113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11113120 is an abundant number, since it is smaller than the sum of its proper divisors (15142004).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11113120 is an equidigital number, since it uses as much as digits as its factorization.
11113120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69472 (or 69464 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 10.
The square root of 11113120 is about 3333.6346530476. The cubic root of 11113120 is about 223.1577640478.
Adding to 11113120 its reverse (2131111), we get a palindrome (13244231).
Subtracting from 11113120 its reverse (2131111), we obtain a square (8982009 = 29972).
It can be divided in two parts, 111 and 13120, that added together give a palindrome (13231).
The spelling of 11113120 in words is "eleven million, one hundred thirteen thousand, one hundred twenty".
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