11113432013 has 2 divisors, whose sum is σ = 11113432014. Its totient is φ = 11113432012.

The previous prime is 11113432009. The next prime is 11113432019. The reversal of 11113432013 is 31023431111.

11113432013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6749772649 + 4363659364 = 82157^2 + 66058^2 .

It is an emirp because it is prime and its reverse (31023431111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11113432013 - 2² = 11113432009 is a prime.

It is a super-2 number, since 2×11113432013² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11113432019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556716006 + 5556716007.

It is an arithmetic number, because the mean of its divisors is an integer number (5556716007).

Almost surely, 2^11113432013 is an apocalyptic number.

It is an amenable number.

11113432013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11113432013 is an equidigital number, since it uses as much as digits as its factorization.

11113432013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11113432013 its reverse (31023431111), we get a palindrome (42136863124).

The spelling of 11113432013 in words is "eleven billion, one hundred thirteen million, four hundred thirty-two thousand, thirteen".