Base | Representation |
---|---|
bin | 110011110000010110… |
… | …1100001101111011111 |
3 | 101121212211110001011210 |
4 | 1213200231201233133 |
5 | 3310110404312341 |
6 | 123020422115503 |
7 | 11013154140534 |
oct | 1474055415737 |
9 | 347784401153 |
10 | 111144213471 |
11 | 43155013685 |
12 | 19659b7bb93 |
13 | a63358b1b5 |
14 | 5545150d8b |
15 | 2d577b3c16 |
hex | 19e0b61bdf |
111144213471 has 8 divisors (see below), whose sum is σ = 148196522160. Its totient is φ = 74094023552.
The previous prime is 111144213431. The next prime is 111144213611. The reversal of 111144213471 is 174312441111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 111144213471 - 218 = 111143951327 is a prime.
It is a super-3 number, since 3×1111442134713 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111144213431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 402960 + ... + 620213.
It is an arithmetic number, because the mean of its divisors is an integer number (18524565270).
Almost surely, 2111144213471 is an apocalyptic number.
111144213471 is a deficient number, since it is larger than the sum of its proper divisors (37052308689).
111144213471 is a wasteful number, since it uses less digits than its factorization.
111144213471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1059385.
The product of its digits is 2688, while the sum is 30.
Adding to 111144213471 its reverse (174312441111), we get a palindrome (285456654582).
The spelling of 111144213471 in words is "one hundred eleven billion, one hundred forty-four million, two hundred thirteen thousand, four hundred seventy-one".
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