11115320153 has 4 divisors (see below), whose sum is σ = 12703223040. Its totient is φ = 9527417268.

The previous prime is 11115320149. The next prime is 11115320159. The reversal of 11115320153 is 35102351111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35102351111 = 17 ⋅2064844183.

It is a cyclic number.

It is not a de Polignac number, because 11115320153 - 2² = 11115320149 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11115320159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 793951433 + ... + 793951446.

It is an arithmetic number, because the mean of its divisors is an integer number (3175805760).

Almost surely, 2^11115320153 is an apocalyptic number.

It is an amenable number.

11115320153 is a deficient number, since it is larger than the sum of its proper divisors (1587902887).

11115320153 is an equidigital number, since it uses as much as digits as its factorization.

11115320153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1587902886.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 11115320153 its reverse (35102351111), we get a palindrome (46217671264).

The spelling of 11115320153 in words is "eleven billion, one hundred fifteen million, three hundred twenty thousand, one hundred fifty-three".