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1111965307513 is a prime number
BaseRepresentation
bin10000001011100110010…
…011000001001001111001
310221022011202220100221021
4100023212103001021321
5121204301104320023
62210455123342441
7143223352110004
oct20134623011171
93838152810837
101111965307513
11399644477695
1215b60ab21a21
1380b1c9b3ca8
143bb6865453b
151ddd116c35d
hex102e64c1279

1111965307513 has 2 divisors, whose sum is σ = 1111965307514. Its totient is φ = 1111965307512.

The previous prime is 1111965307489. The next prime is 1111965307517. The reversal of 1111965307513 is 3157035691111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 907071474409 + 204893833104 = 952403^2 + 452652^2 .

It is a cyclic number.

It is not a de Polignac number, because 1111965307513 - 221 = 1111963210361 is a prime.

It is a super-2 number, since 2×11119653075132 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1111965307513.

It is not a weakly prime, because it can be changed into another prime (1111965307517) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555982653756 + 555982653757.

It is an arithmetic number, because the mean of its divisors is an integer number (555982653757).

Almost surely, 21111965307513 is an apocalyptic number.

It is an amenable number.

1111965307513 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111965307513 is an equidigital number, since it uses as much as digits as its factorization.

1111965307513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 85050, while the sum is 43.

The spelling of 1111965307513 in words is "one trillion, one hundred eleven billion, nine hundred sixty-five million, three hundred seven thousand, five hundred thirteen".