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11120000002031 is a prime number
BaseRepresentation
bin1010000111010001001110…
…1001100110011111101111
31110101001122220211101121002
42201310103221212133233
52424142230000031111
635352242452030515
72225251652314544
oct241642351463757
943331586741532
1011120000002031
1135a7a69115608
1212b716960243b
136287c460c30b
142a62d48bcbcb
151443cb66063b
hexa1d13a667ef

11120000002031 has 2 divisors, whose sum is σ = 11120000002032. Its totient is φ = 11120000002030.

The previous prime is 11120000001991. The next prime is 11120000002049. The reversal of 11120000002031 is 13020000002111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11120000002031 is a prime.

It is a super-3 number, since 3×111200000020313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11120000002091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560000001015 + 5560000001016.

It is an arithmetic number, because the mean of its divisors is an integer number (5560000001016).

Almost surely, 211120000002031 is an apocalyptic number.

11120000002031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11120000002031 is an equidigital number, since it uses as much as digits as its factorization.

11120000002031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 11120000002031 its reverse (13020000002111), we get a palindrome (24140000004142).

The spelling of 11120000002031 in words is "eleven trillion, one hundred twenty billion, two thousand, thirty-one".