Base | Representation |
---|---|
bin | 11001010010001011000100… |
… | …100100111001110111110010 |
3 | 112120201121122021201001002211 |
4 | 121102023010210321313302 |
5 | 104033400100313131002 |
6 | 1032300324140202334 |
7 | 32264635460344534 |
oct | 3122130444716762 |
9 | 476647567631084 |
10 | 111200001302002 |
11 | 32482723836518 |
12 | 1057b37b5393aa |
13 | 4a08165c23982 |
14 | 1d661746c7854 |
15 | ccc8795a8dd7 |
hex | 6522c4939df2 |
111200001302002 has 4 divisors (see below), whose sum is σ = 166800001953006. Its totient is φ = 55600000651000.
The previous prime is 111200001301967. The next prime is 111200001302003. The reversal of 111200001302002 is 200203100002111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 68946634234921 + 42253367067081 = 8303411^2 + 6500259^2 .
It is not an unprimeable number, because it can be changed into a prime (111200001302003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27800000325499 + ... + 27800000325502.
Almost surely, 2111200001302002 is an apocalyptic number.
111200001302002 is a deficient number, since it is larger than the sum of its proper divisors (55600000651004).
111200001302002 is an equidigital number, since it uses as much as digits as its factorization.
111200001302002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55600000651003.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 111200001302002 its reverse (200203100002111), we get a palindrome (311403101304113).
The spelling of 111200001302002 in words is "one hundred eleven trillion, two hundred billion, one million, three hundred two thousand, two".
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