11120022013 has 2 divisors, whose sum is σ = 11120022014. Its totient is φ = 11120022012.

The previous prime is 11120021999. The next prime is 11120022029. The reversal of 11120022013 is 31022002111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6760457284 + 4359564729 = 82222^2 + 66027^2 .

It is an emirp because it is prime and its reverse (31022002111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11120022013 - 2⁵ = 11120021981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11120021984 and 11120022002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11120022413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560011006 + 5560011007.

It is an arithmetic number, because the mean of its divisors is an integer number (5560011007).

Almost surely, 2^11120022013 is an apocalyptic number.

It is an amenable number.

11120022013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11120022013 is an equidigital number, since it uses as much as digits as its factorization.

11120022013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 11120022013 its reverse (31022002111), we get a palindrome (42142024124).

The spelling of 11120022013 in words is "eleven billion, one hundred twenty million, twenty-two thousand, thirteen".