Base | Representation |
---|---|
bin | 10000001011101000100… |
… | …000101001010111100111 |
3 | 10221022021100202121122011 |
4 | 100023220200221113213 |
5 | 121204340110401120 |
6 | 2210502531215051 |
7 | 143224312511026 |
oct | 20135040512747 |
9 | 3838240677564 |
10 | 1112002434535 |
11 | 399663425783 |
12 | 15b61b447487 |
13 | 80b275b2c45 |
14 | 3bb6d55a8bd |
15 | 1ddd4552c5a |
hex | 102e88295e7 |
1112002434535 has 4 divisors (see below), whose sum is σ = 1334402921448. Its totient is φ = 889601947624.
The previous prime is 1112002434493. The next prime is 1112002434563. The reversal of 1112002434535 is 5354342002111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1112002434535 - 211 = 1112002432487 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1112002434497 and 1112002434506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111200243449 + ... + 111200243458.
It is an arithmetic number, because the mean of its divisors is an integer number (333600730362).
Almost surely, 21112002434535 is an apocalyptic number.
1112002434535 is a deficient number, since it is larger than the sum of its proper divisors (222400486913).
1112002434535 is an equidigital number, since it uses as much as digits as its factorization.
1112002434535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 222400486912.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1112002434535 its reverse (5354342002111), we get a palindrome (6466344436646).
The spelling of 1112002434535 in words is "one trillion, one hundred twelve billion, two million, four hundred thirty-four thousand, five hundred thirty-five".
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