Search a number
-
+
1112011131302 = 2556005565651
BaseRepresentation
bin10000001011101001000…
…001110100100110100110
310221022021222010110100122
4100023221001310212212
5121204344322200202
62210503441441542
7143224446442031
oct20135101644646
93838258113318
101112011131302
11399668325795
1215b6223402b2
1380b29339566
143bb70782018
151ddd51be9a2
hex102e90749a6

1112011131302 has 4 divisors (see below), whose sum is σ = 1668016696956. Its totient is φ = 556005565650.

The previous prime is 1112011131299. The next prime is 1112011131307. The reversal of 1112011131302 is 2031311102111.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×11120111313022 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1112011131307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278002782824 + ... + 278002782827.

It is an arithmetic number, because the mean of its divisors is an integer number (417004174239).

Almost surely, 21112011131302 is an apocalyptic number.

1112011131302 is a deficient number, since it is larger than the sum of its proper divisors (556005565654).

1112011131302 is an equidigital number, since it uses as much as digits as its factorization.

1112011131302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 556005565653.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1112011131302 its reverse (2031311102111), we get a palindrome (3143322233413).

The spelling of 1112011131302 in words is "one trillion, one hundred twelve billion, eleven million, one hundred thirty-one thousand, three hundred two".

Divisors: 1 2 556005565651 1112011131302