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1112013101113 is a prime number
BaseRepresentation
bin10000001011101001001…
…001010101100000111001
310221022022002211112102121
4100023221021111200321
5121204400323213423
62210503552001241
7143224502254645
oct20135111254071
93838262745377
101112013101113
11399669450732
1215b622b30221
1380b29879025
143bb70b35c25
151ddd545d45d
hex102e9255839

1112013101113 has 2 divisors, whose sum is σ = 1112013101114. Its totient is φ = 1112013101112.

The previous prime is 1112013101093. The next prime is 1112013101159. The reversal of 1112013101113 is 3111013102111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1101569896249 + 10443204864 = 1049557^2 + 102192^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1112013101113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1112013108113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556006550556 + 556006550557.

It is an arithmetic number, because the mean of its divisors is an integer number (556006550557).

Almost surely, 21112013101113 is an apocalyptic number.

It is an amenable number.

1112013101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112013101113 is an equidigital number, since it uses as much as digits as its factorization.

1112013101113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 1112013101113 its reverse (3111013102111), we get a palindrome (4223026203224).

The spelling of 1112013101113 in words is "one trillion, one hundred twelve billion, thirteen million, one hundred one thousand, one hundred thirteen".