Base | Representation |
---|---|
bin | 101101010001010110110… |
… | …101001011001000011111 |
3 | 102000102001212000011122121 |
4 | 231101112311023020133 |
5 | 401432323323231421 |
6 | 10341102451323411 |
7 | 440522543025025 |
oct | 55212665131037 |
9 | 12012055004577 |
10 | 3111013102111 |
11 | a9a411879462 |
12 | 422b27bb0567 |
13 | 1974a0ba37c5 |
14 | aa806878715 |
15 | 55dd0759d41 |
hex | 2d456d4b21f |
3111013102111 has 4 divisors (see below), whose sum is σ = 3163742137800. Its totient is φ = 3058284066424.
The previous prime is 3111013102073. The next prime is 3111013102117. The reversal of 3111013102111 is 1112013101113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3111013102111 - 27 = 3111013101983 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3111013102117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26364517756 + ... + 26364517873.
It is an arithmetic number, because the mean of its divisors is an integer number (790935534450).
Almost surely, 23111013102111 is an apocalyptic number.
3111013102111 is a deficient number, since it is larger than the sum of its proper divisors (52729035689).
3111013102111 is an equidigital number, since it uses as much as digits as its factorization.
3111013102111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52729035688.
The product of its (nonzero) digits is 18, while the sum is 16.
Adding to 3111013102111 its reverse (1112013101113), we get a palindrome (4223026203224).
The spelling of 3111013102111 in words is "three trillion, one hundred eleven billion, thirteen million, one hundred two thousand, one hundred eleven".
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