Base | Representation |
---|---|
bin | 11001010010001100111100… |
… | …010011100011100011001011 |
3 | 112120201210211021110111020022 |
4 | 121102030330103203203023 |
5 | 104033413204031120133 |
6 | 1032301255334051055 |
7 | 32265036321226415 |
oct | 3122147423434313 |
9 | 476653737414208 |
10 | 111202010020043 |
11 | 32483564698078 |
12 | 1057b8401a9a8b |
13 | 4a083c6131227 |
14 | 1d662c53b19b5 |
15 | ccc945ade998 |
hex | 65233c4e38cb |
111202010020043 has 2 divisors, whose sum is σ = 111202010020044. Its totient is φ = 111202010020042.
The previous prime is 111202010019983. The next prime is 111202010020061. The reversal of 111202010020043 is 340020010202111.
It is a strong prime.
It is an emirp because it is prime and its reverse (340020010202111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111202010020043 - 214 = 111202010003659 is a prime.
It is not a weakly prime, because it can be changed into another prime (111202010010043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55601005010021 + 55601005010022.
It is an arithmetic number, because the mean of its divisors is an integer number (55601005010022).
Almost surely, 2111202010020043 is an apocalyptic number.
111202010020043 is a deficient number, since it is larger than the sum of its proper divisors (1).
111202010020043 is an equidigital number, since it uses as much as digits as its factorization.
111202010020043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 111202010020043 its reverse (340020010202111), we get a palindrome (451222020222154).
The spelling of 111202010020043 in words is "one hundred eleven trillion, two hundred two billion, ten million, twenty thousand, forty-three".
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