Base | Representation |
---|---|
bin | 10000001011101001101… |
… | …100000011001100101011 |
3 | 10221022022201221212022022 |
4 | 100023221230003030223 |
5 | 121204410140414011 |
6 | 2210504515015055 |
7 | 143224642515422 |
oct | 20135154031453 |
9 | 3838281855268 |
10 | 1112022201131 |
11 | 3996735a6706 |
12 | 15b625b9a48b |
13 | 80b2b71405a |
14 | 3bb720242b9 |
15 | 1ddd61598db |
hex | 102e9b0332b |
1112022201131 has 2 divisors, whose sum is σ = 1112022201132. Its totient is φ = 1112022201130.
The previous prime is 1112022201053. The next prime is 1112022201161. The reversal of 1112022201131 is 1311022202111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1112022201131 is a prime.
It is a super-2 number, since 2×11120222011312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1112022201161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556011100565 + 556011100566.
It is an arithmetic number, because the mean of its divisors is an integer number (556011100566).
Almost surely, 21112022201131 is an apocalyptic number.
1112022201131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1112022201131 is an equidigital number, since it uses as much as digits as its factorization.
1112022201131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1112022201131 its reverse (1311022202111), we get a palindrome (2423044403242).
The spelling of 1112022201131 in words is "one trillion, one hundred twelve billion, twenty-two million, two hundred one thousand, one hundred thirty-one".
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