1112100101113 has 8 divisors (see below), whose sum is σ = 1135791157248. Its totient is φ = 1088410268064.

The previous prime is 1112100101083. The next prime is 1112100101137. The reversal of 1112100101113 is 3111010012111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1112100101113 is a prime.

It is a super-3 number, since 3×1112100101113³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1112100101093 and 1112100101102.

It is not an unprimeable number, because it can be changed into a prime (1112100101143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1666120 + ... + 2236102.

It is an arithmetic number, because the mean of its divisors is an integer number (141973894656).

Almost surely, 2^{1112100101113} is an apocalyptic number.

It is an amenable number.

1112100101113 is a deficient number, since it is larger than the sum of its proper divisors (23691056135).

1112100101113 is an equidigital number, since it uses as much as digits as its factorization.

1112100101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 611543.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 1112100101113 its reverse (3111010012111), we get a palindrome (4223110113224).

The spelling of 1112100101113 in words is "one trillion, one hundred twelve billion, one hundred million, one hundred one thousand, one hundred thirteen".