Base | Representation |
---|---|
bin | 1010000111010101010100… |
… | …1101110011101001000111 |
3 | 1110101011111120200200201212 |
4 | 2201311111031303221013 |
5 | 2424202003100341403 |
6 | 35352543545042035 |
7 | 2225321140252154 |
oct | 241652515635107 |
9 | 43334446620655 |
10 | 11121100012103 |
11 | 35a8483037444 |
12 | 12b7415a8631b |
13 | 62893b494753 |
14 | 2a639aa2122b |
15 | 144442ee94d8 |
hex | a1d55373a47 |
11121100012103 has 2 divisors, whose sum is σ = 11121100012104. Its totient is φ = 11121100012102.
The previous prime is 11121100012097. The next prime is 11121100012129. The reversal of 11121100012103 is 30121000112111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11121100012103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11121100012703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560550006051 + 5560550006052.
It is an arithmetic number, because the mean of its divisors is an integer number (5560550006052).
Almost surely, 211121100012103 is an apocalyptic number.
11121100012103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121100012103 is an equidigital number, since it uses as much as digits as its factorization.
11121100012103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 11121100012103 its reverse (30121000112111), we get a palindrome (41242100124214).
The spelling of 11121100012103 in words is "eleven trillion, one hundred twenty-one billion, one hundred million, twelve thousand, one hundred three".
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