Base | Representation |
---|---|
bin | 11001010010010101011010… |
… | …000111000100111101011101 |
3 | 112120202200021202212022200002 |
4 | 121102111122013010331131 |
5 | 104034040313100000333 |
6 | 1032305401331544045 |
7 | 32265510505621112 |
oct | 3122253207047535 |
9 | 476680252768602 |
10 | 111211100000093 |
11 | 324873a9756685 |
12 | 1058155845b025 |
13 | 4a09214427352 |
14 | 1d6690872a909 |
15 | ccccc8b420e8 |
hex | 65255a1c4f5d |
111211100000093 has 2 divisors, whose sum is σ = 111211100000094. Its totient is φ = 111211100000092.
The previous prime is 111211100000051. The next prime is 111211100000123. The reversal of 111211100000093 is 390000001112111.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 99727425995044 + 11483674005049 = 9986362^2 + 3388757^2 .
It is a cyclic number.
It is not a de Polignac number, because 111211100000093 - 226 = 111211032891229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111211100000893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55605550000046 + 55605550000047.
It is an arithmetic number, because the mean of its divisors is an integer number (55605550000047).
Almost surely, 2111211100000093 is an apocalyptic number.
It is an amenable number.
111211100000093 is a deficient number, since it is larger than the sum of its proper divisors (1).
111211100000093 is an equidigital number, since it uses as much as digits as its factorization.
111211100000093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 20.
The spelling of 111211100000093 in words is "one hundred eleven trillion, two hundred eleven billion, one hundred million, ninety-three", and thus it is an aban number.
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