111211112112 has 80 divisors (see below), whose sum is σ = 299950801920. Its totient is φ = 35439179776.

The previous prime is 111211112083. The next prime is 111211112141. The reversal of 111211112112 is 211211112111.

It is an interprime number because it is at equal distance from previous prime (111211112083) and next prime (111211112141).

It is a super-2 number, since 2×111211112112² (a number of 23 digits) contains 22 as substring.

It is a nude number because it is divisible by every one of its digits and also a Zuckerman number because it is divisible by the product of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 111211112091 and 111211112100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2058793 + ... + 2112119.

It is an arithmetic number, because the mean of its divisors is an integer number (3749385024).

Almost surely, 2^111211112112 is an apocalyptic number.

111211112112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 111211112112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (149975400960).

111211112112 is an abundant number, since it is smaller than the sum of its proper divisors (188739689808).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111211112112 is a wasteful number, since it uses less digits than its factorization.

111211112112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55250 (or 55244 counting only the distinct ones).

The product of its digits is 8, while the sum is 15.

Adding to 111211112112 its reverse (211211112111), we get a palindrome (322422224223).

Subtracting 111211112112 from its reverse (211211112111), we obtain a palindrome (99999999999).

The spelling of 111211112112 in words is "one hundred eleven billion, two hundred eleven million, one hundred twelve thousand, one hundred twelve".