Base | Representation |
---|---|
bin | 11001010010010101100000… |
… | …101010110001110011101001 |
3 | 112120202200120102220000112000 |
4 | 121102111200222301303221 |
5 | 104034041024231201441 |
6 | 1032305420302041213 |
7 | 32265513313034046 |
oct | 3122254052616351 |
9 | 476680512800460 |
10 | 111211210022121 |
11 | 32487455872880 |
12 | 10581589279209 |
13 | 4a09231169741 |
14 | 1d669191aa1cd |
15 | ccccd36262b6 |
hex | 652560ab1ce9 |
111211210022121 has 16 divisors (see below), whose sum is σ = 179735288925120. Its totient is φ = 67400733346560.
The previous prime is 111211210022119. The next prime is 111211210022179. The reversal of 111211210022121 is 121220012112111.
It is a happy number.
111211210022121 is a `hidden beast` number, since 1 + 1 + 1 + 211 + 210 + 0 + 221 + 21 = 666.
It is not a de Polignac number, because 111211210022121 - 21 = 111211210022119 is a prime.
It is a super-3 number, since 3×1112112100221213 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111211210022094 and 111211210022103.
It is not an unprimeable number, because it can be changed into a prime (111211210022821) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 187224259000 + ... + 187224259593.
It is an arithmetic number, because the mean of its divisors is an integer number (11233455557820).
Almost surely, 2111211210022121 is an apocalyptic number.
111211210022121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
111211210022121 is a deficient number, since it is larger than the sum of its proper divisors (68524078902999).
111211210022121 is a wasteful number, since it uses less digits than its factorization.
111211210022121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 374448518613 (or 374448518607 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 18.
Adding to 111211210022121 its reverse (121220012112111), we get a palindrome (232431222134232).
The spelling of 111211210022121 in words is "one hundred eleven trillion, two hundred eleven billion, two hundred ten million, twenty-two thousand, one hundred twenty-one".
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