Base | Representation |
---|---|
bin | 1010000111010101011010… |
… | …0001101011110100001111 |
3 | 1110101011120010001210122201 |
4 | 2201311112201223310033 |
5 | 2424202024213001033 |
6 | 35352550052222331 |
7 | 2225321525201221 |
oct | 241652641536417 |
9 | 43334503053581 |
10 | 11121122000143 |
11 | 35a8494495381 |
12 | 12b742130a9a7 |
13 | 628942bc2a1c |
14 | 2a639d906411 |
15 | 144444dde47d |
hex | a1d5686bd0f |
11121122000143 has 2 divisors, whose sum is σ = 11121122000144. Its totient is φ = 11121122000142.
The previous prime is 11121122000117. The next prime is 11121122000239. The reversal of 11121122000143 is 34100022112111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11121122000143 - 229 = 11120585129231 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11121122000143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11121122000243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560561000071 + 5560561000072.
It is an arithmetic number, because the mean of its divisors is an integer number (5560561000072).
Almost surely, 211121122000143 is an apocalyptic number.
11121122000143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121122000143 is an equidigital number, since it uses as much as digits as its factorization.
11121122000143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 11121122000143 its reverse (34100022112111), we get a palindrome (45221144112254).
The spelling of 11121122000143 in words is "eleven trillion, one hundred twenty-one billion, one hundred twenty-two million, one hundred forty-three", and thus it is an aban number.
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