Base | Representation |
---|---|
bin | 110011110010010110… |
… | …1001000110010010101 |
3 | 101122001111112100000102 |
4 | 1213210231020302111 |
5 | 3310230033020432 |
6 | 123031214223445 |
7 | 11014626526304 |
oct | 1474455106225 |
9 | 348044470012 |
10 | 111211220117 |
11 | 4318991a778 |
12 | 196784b4b85 |
13 | a64441c3ba |
14 | 554ddd443b |
15 | 2d5d5ec962 |
hex | 19e4b48c95 |
111211220117 has 2 divisors, whose sum is σ = 111211220118. Its totient is φ = 111211220116.
The previous prime is 111211220093. The next prime is 111211220149. The reversal of 111211220117 is 711022112111.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 108714618961 + 2496601156 = 329719^2 + 49966^2 .
It is an emirp because it is prime and its reverse (711022112111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111211220117 - 212 = 111211216021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111211223117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55605610058 + 55605610059.
It is an arithmetic number, because the mean of its divisors is an integer number (55605610059).
Almost surely, 2111211220117 is an apocalyptic number.
It is an amenable number.
111211220117 is a deficient number, since it is larger than the sum of its proper divisors (1).
111211220117 is an equidigital number, since it uses as much as digits as its factorization.
111211220117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 111211220117 its reverse (711022112111), we get a palindrome (822233332228).
The spelling of 111211220117 in words is "one hundred eleven billion, two hundred eleven million, two hundred twenty thousand, one hundred seventeen".
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