1112113213333 has 4 divisors (see below), whose sum is σ = 1130344577548. Its totient is φ = 1093881849120.

The previous prime is 1112113213303. The next prime is 1112113213363. The reversal of 1112113213333 is 3333123112111.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1112113213303) and next prime (1112113213363).

It can be written as a sum of positive squares in 2 ways, for example, as 40095256644 + 1072017956689 = 200238^2 + 1035383^2 .

It is a cyclic number.

It is not a de Polignac number, because 1112113213333 - 2¹³ = 1112113205141 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1112113213298 and 1112113213307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1112113213303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9115682016 + ... + 9115682137.

It is an arithmetic number, because the mean of its divisors is an integer number (282586144387).

Almost surely, 2^{1112113213333} is an apocalyptic number.

It is an amenable number.

1112113213333 is a deficient number, since it is larger than the sum of its proper divisors (18231364215).

1112113213333 is an equidigital number, since it uses as much as digits as its factorization.

1112113213333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18231364214.

The product of its digits is 972, while the sum is 25.

Adding to 1112113213333 its reverse (3333123112111), we get a palindrome (4445236325444).

The spelling of 1112113213333 in words is "one trillion, one hundred twelve billion, one hundred thirteen million, two hundred thirteen thousand, three hundred thirty-three".