Base | Representation |
---|---|
bin | 1010000111010101101111… |
… | …1110000001000100100111 |
3 | 1110101011210110212222210012 |
4 | 2201311123332001010213 |
5 | 2424202221102011234 |
6 | 35353003113320435 |
7 | 2225324014303334 |
oct | 241653376010447 |
9 | 43334713788705 |
10 | 11121213313319 |
11 | 35a8530a9330a |
12 | 12b7447a0611b |
13 | 628958ab45a5 |
14 | 2a63abab598b |
15 | 14444ce2a0ce |
hex | a1d5bf81127 |
11121213313319 has 2 divisors, whose sum is σ = 11121213313320. Its totient is φ = 11121213313318.
The previous prime is 11121213313303. The next prime is 11121213313321. The reversal of 11121213313319 is 91331331212111.
11121213313319 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11121213313319 - 24 = 11121213313303 is a prime.
It is a super-2 number, since 2×111212133133192 (a number of 27 digits) contains 22 as substring.
Together with 11121213313321, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11121213313369) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560606656659 + 5560606656660.
It is an arithmetic number, because the mean of its divisors is an integer number (5560606656660).
Almost surely, 211121213313319 is an apocalyptic number.
11121213313319 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121213313319 is an equidigital number, since it uses as much as digits as its factorization.
11121213313319 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2916, while the sum is 32.
The spelling of 11121213313319 in words is "eleven trillion, one hundred twenty-one billion, two hundred thirteen million, three hundred thirteen thousand, three hundred nineteen".
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