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111213001300319 is a prime number
BaseRepresentation
bin11001010010010111001011…
…011011111101100101011111
3112120202212012021111101020222
4121102113023123331211133
5104034103211313102234
61032310314131231555
732265605563454342
oct3122271333754537
9476685167441228
10111213001300319
1132488194a0a686
12105819a91485bb
134a094582c4979
141d66a49052459
15cccd8aa0a42e
hex6525cb6fd95f

111213001300319 has 2 divisors, whose sum is σ = 111213001300320. Its totient is φ = 111213001300318.

The previous prime is 111213001300273. The next prime is 111213001300321. The reversal of 111213001300319 is 913003100312111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111213001300319 is a prime.

It is a super-2 number, since 2×1112130013003192 (a number of 29 digits) contains 22 as substring.

Together with 111213001300321, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111213001300369) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55606500650159 + 55606500650160.

It is an arithmetic number, because the mean of its divisors is an integer number (55606500650160).

Almost surely, 2111213001300319 is an apocalyptic number.

111213001300319 is a deficient number, since it is larger than the sum of its proper divisors (1).

111213001300319 is an equidigital number, since it uses as much as digits as its factorization.

111213001300319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 26.

The spelling of 111213001300319 in words is "one hundred eleven trillion, two hundred thirteen billion, one million, three hundred thousand, three hundred nineteen".