Base | Representation |
---|---|
bin | 110011110010011010… |
… | …0010110101111101101 |
3 | 101122001122002110121022 |
4 | 1213210310112233231 |
5 | 3310231024043201 |
6 | 123031322543525 |
7 | 11014651600004 |
oct | 1474464265755 |
9 | 348048073538 |
10 | 111213112301 |
11 | 4318a9a2365 |
12 | 19679067ba5 |
13 | a644932735 |
14 | 5550367c3b |
15 | 2d5d87341b |
hex | 19e4d16bed |
111213112301 has 2 divisors, whose sum is σ = 111213112302. Its totient is φ = 111213112300.
The previous prime is 111213112271. The next prime is 111213112321. The reversal of 111213112301 is 103211312111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 104216626276 + 6996486025 = 322826^2 + 83645^2 .
It is a cyclic number.
It is not a de Polignac number, because 111213112301 - 210 = 111213111277 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 111213112301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111213112321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55606556150 + 55606556151.
It is an arithmetic number, because the mean of its divisors is an integer number (55606556151).
Almost surely, 2111213112301 is an apocalyptic number.
It is an amenable number.
111213112301 is a deficient number, since it is larger than the sum of its proper divisors (1).
111213112301 is an equidigital number, since it uses as much as digits as its factorization.
111213112301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 111213112301 its reverse (103211312111), we get a palindrome (214424424412).
The spelling of 111213112301 in words is "one hundred eleven billion, two hundred thirteen million, one hundred twelve thousand, three hundred one".
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