1112131420013 has 2 divisors, whose sum is σ = 1112131420014. Its totient is φ = 1112131420012.

The previous prime is 1112131419983. The next prime is 1112131420031. The reversal of 1112131420013 is 3100241312111.

Together with next prime (1112131420031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 736708072489 + 375423347524 = 858317^2 + 612718^2 .

It is an emirp because it is prime and its reverse (3100241312111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1112131420013 - 2¹⁴ = 1112131403629 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1112131420913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556065710006 + 556065710007.

It is an arithmetic number, because the mean of its divisors is an integer number (556065710007).

Almost surely, 2^{1112131420013} is an apocalyptic number.

It is an amenable number.

1112131420013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112131420013 is an equidigital number, since it uses as much as digits as its factorization.

1112131420013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1112131420013 its reverse (3100241312111), we get a palindrome (4212372732124).

The spelling of 1112131420013 in words is "one trillion, one hundred twelve billion, one hundred thirty-one million, four hundred twenty thousand, thirteen".