1112131420031 has 2 divisors, whose sum is σ = 1112131420032. Its totient is φ = 1112131420030.

The previous prime is 1112131420013. The next prime is 1112131420061. The reversal of 1112131420031 is 1300241312111.

Together with previous prime (1112131420013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1112131420031 is a prime.

It is a super-2 number, since 2×1112131420031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1112131419985 and 1112131420012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1112131420061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556065710015 + 556065710016.

It is an arithmetic number, because the mean of its divisors is an integer number (556065710016).

Almost surely, 2^{1112131420031} is an apocalyptic number.

1112131420031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112131420031 is an equidigital number, since it uses as much as digits as its factorization.

1112131420031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1112131420031 its reverse (1300241312111), we get a palindrome (2412372732142).

The spelling of 1112131420031 in words is "one trillion, one hundred twelve billion, one hundred thirty-one million, four hundred twenty thousand, thirty-one".