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11122040131 is a prime number
BaseRepresentation
bin10100101101110110…
…01101110101000011
31001201010002011211021
422112323031311003
5140234220241011
65035343530311
7542420531656
oct122673156503
931633064737
1011122040131
114798113404
1221a48b9997
1310832b7047
1477719b89d
15451649471
hex296ecdd43

11122040131 has 2 divisors, whose sum is σ = 11122040132. Its totient is φ = 11122040130.

The previous prime is 11122040129. The next prime is 11122040141. The reversal of 11122040131 is 13104022111.

It is a weak prime.

It is an emirp because it is prime and its reverse (13104022111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11122040131 - 21 = 11122040129 is a prime.

It is a super-2 number, since 2×111220401312 (a number of 21 digits) contains 22 as substring.

Together with 11122040129, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11122040141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561020065 + 5561020066.

It is an arithmetic number, because the mean of its divisors is an integer number (5561020066).

Almost surely, 211122040131 is an apocalyptic number.

11122040131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11122040131 is an equidigital number, since it uses as much as digits as its factorization.

11122040131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11122040131 its reverse (13104022111), we get a palindrome (24226062242).

The spelling of 11122040131 in words is "eleven billion, one hundred twenty-two million, forty thousand, one hundred thirty-one".