13104022111 has 2 divisors, whose sum is σ = 13104022112. Its totient is φ = 13104022110.

The previous prime is 13104022091. The next prime is 13104022123. The reversal of 13104022111 is 11122040131.

13104022111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (11122040131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13104022111 - 2⁵ = 13104022079 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104022171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552011055 + 6552011056.

It is an arithmetic number, because the mean of its divisors is an integer number (6552011056).

Almost surely, 2^13104022111 is an apocalyptic number.

13104022111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104022111 is an equidigital number, since it uses as much as digits as its factorization.

13104022111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13104022111 its reverse (11122040131), we get a palindrome (24226062242).

The spelling of 13104022111 in words is "thirteen billion, one hundred four million, twenty-two thousand, one hundred eleven".