1112210120143 has 2 divisors, whose sum is σ = 1112210120144. Its totient is φ = 1112210120142.

The previous prime is 1112210120083. The next prime is 1112210120167. The reversal of 1112210120143 is 3410210122111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1112210120143 is a prime.

It is a super-2 number, since 2×1112210120143² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1112210120143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1112210120173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556105060071 + 556105060072.

It is an arithmetic number, because the mean of its divisors is an integer number (556105060072).

Almost surely, 2^{1112210120143} is an apocalyptic number.

1112210120143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112210120143 is an equidigital number, since it uses as much as digits as its factorization.

1112210120143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 1112210120143 its reverse (3410210122111), we get a palindrome (4522420242254).

It can be divided in two parts, 11122101 and 20143, that added together give a square (11142244 = 3338²).

The spelling of 1112210120143 in words is "one trillion, one hundred twelve billion, two hundred ten million, one hundred twenty thousand, one hundred forty-three".